Répondre :
développement:
4-(x+3)²
=4-(x²+6x+9)
=4-x²-6x-9
=-x²-6x-5
factorisation:
4-(x+3)²
=[2-(x+3)][2+(x+3)]
=(2-x-3)(2+x+3)
=(-x-1)(x+5)
4-(x+3)²
=4-(x²+6x+9)
=4-x²-6x-9
=-x²-6x-5
factorisation:
4-(x+3)²
=[2-(x+3)][2+(x+3)]
=(2-x-3)(2+x+3)
=(-x-1)(x+5)