Répondre :
z1=1+3i et z2=2-2i
donc
z1+z2=1+3i+2-2i
=3+i
z2-2z1"barre"=2-2i-2(1-3i)
=4i
z1*z2=(1+3i)(2-2i)
=2-2i+6i+6
=8+4i
(z2)²=(2-2i)²
=4-8i-4
=-8i
(1-z1)(1+z2)=(-3i)(3-2i)
=-6-9i
donc
z1+z2=1+3i+2-2i
=3+i
z2-2z1"barre"=2-2i-2(1-3i)
=4i
z1*z2=(1+3i)(2-2i)
=2-2i+6i+6
=8+4i
(z2)²=(2-2i)²
=4-8i-4
=-8i
(1-z1)(1+z2)=(-3i)(3-2i)
=-6-9i
a) z1 + z2
= (1+3i) + (2-2i)
= 1+ 3i + 2 -2i
= 3+ i
b) 2 - 2i - 2(1-3i)
= 2-2i - 2 +6i
= 4i
c)(1+3i)(2-2i)
= 2 - 2i +6i -6i²
= -6i² -4i +2
d) (2-2i)²
= 2² -4i + 4i²
=4i²-4i+4
e) (1-(1+3i))(1+2-2i)
= (-3i)(3-2i)
= -9i+6i²
Je ne suis pas sûre de moi
= (1+3i) + (2-2i)
= 1+ 3i + 2 -2i
= 3+ i
b) 2 - 2i - 2(1-3i)
= 2-2i - 2 +6i
= 4i
c)(1+3i)(2-2i)
= 2 - 2i +6i -6i²
= -6i² -4i +2
d) (2-2i)²
= 2² -4i + 4i²
=4i²-4i+4
e) (1-(1+3i))(1+2-2i)
= (-3i)(3-2i)
= -9i+6i²
Je ne suis pas sûre de moi