Répondre :
(2x+5)²=4x²+20x+25
(3-x)(x-2)=3x-6-x²+2x=5x-x²-6si (2x+5)² = (3-x)(x-2) alors
4x²+20x+25=5x-x²-6
5x²+15x+31=0
developper reduire D= (2x+5)² = (3-x)(x-2)
(2x+5)²=4x²+20x+25
(3-x)(x-2)=3x-6-x²+2x=5x-x²-6si (2x+5)² = (3-x)(x-2) alors
4x²+20x+25=5x-x²-6
5x²+15x+31=0
