Répondre :
B = x²-6x+9-(nx-2n-x+2)
= x² -6x+9-nx+2n+x-2
= x² -nx+2n55x+7
C= 16a²-6a-8a+3 -(16a²-16a+4)
= 16a²-6a-8a+3-16a²+16a-4
= 2a-1
pouvez vous m'aider a calculer
B= (x-3)²-(n-1)(x-2)
C= (2a-1)(8a-3)-(4a-2)²
en mettant les étapes merci d'avance
B = x²-6x+9-(nx-2n-x+2)
= x² -6x+9-nx+2n+x-2
= x² -nx+2n55x+7
C= 16a²-6a-8a+3 -(16a²-16a+4)
= 16a²-6a-8a+3-16a²+16a-4
= 2a-1