Répondre :
Bonjour,
[tex]\mathrm{A} = \left(\frac{3}{4}+x\right)^2 = x^2+\frac{3}{2}x+\frac{9}{16}\\ \mathrm{B} = \left(3x-\frac{2}{3}\right) = 9x^2-4x+\frac{4}{9}\\ \mathrm{C} = \left(\frac{5}{2}-\frac{1}{3}\right)\left(\frac{5}{2}+\frac{1}{3}\right) = \frac{25}{4} - \frac{1}{9}[/tex]
A = (3/4 + x)²
A = 0,75² + 2*(3/4)*x + x²
A =x² + 1,5x + 0,5625
B = (3x - 2/3)²
B = (3x)² - 2*3x*(2/3) + (2/3)²
B = 9x² - 4x + (2/3)²