bonjour
droite d 1
d ( 3 ) = 2 et d ( - 2 ) = - 1
( - 1 - 2 ) : ( - 2 - 3 ) = - 3 / - 5 = 3 /5
d ( 3 ) = 2
3 * 3/5 + b = 2 ⇔ b = 2 - 9/5 = 2 - 1.8 = 0.2
f (x) = 3 x /5 + 0.2
d2
d( 0 ) = 2 et d ( 1 ) = 1
( 1 - 2 ) / ( 1 - 0 ) = - 1 /1 = - 1
d (0) = 2 donc b = 2
g (x) = - x + 2
d3
d ( 0 ) = - 1 et d ( 1 ) = 2
( 2 + 1 ) / ( 1 - 0 ) = 3 /1 = 3
d ( 0 ) = - 1 donc b = - 1
h (x) = 3 x - 1
d 4
d (0) = 1 et d ( 1 ) = - 1
( - 1 - 1 ) / ( 1 - 0 ) = - 2 /1 = - 2
d ( 0) = 1 donc b = 1
i (x) = - 2 x + 1
d 5
d ( 0 ) = - 1 et d ( 1 ) = - 2
( - 2 + 1 ) / ( 1 - 0 ) = - 1 /1 = - 1
d (0) = - 1 donc b = - 1
j (x) = - x - 1
d 6 = - 2 fonction constante
tu as maintenant toutes les fonctions pour pouvoir répondre aux questions
Bon WE
