Répondre :
p(ABC)=AB+AC+CB
AB=6/sin(60°)=6/(√3/2)=12/√3=4√3
AC=6/sin(45°)=12/√2=6√2
BC=BH+HC
=6/tan(60°)+6/tan(45°)
=6/√3+6/1
=2√3+6
donc p(ABC)=4√3+6√2+2√3+6
=6+6√3+6√2
=6(√3+1+√2)
AB=6/sin(60°)=6/(√3/2)=12/√3=4√3
AC=6/sin(45°)=12/√2=6√2
BC=BH+HC
=6/tan(60°)+6/tan(45°)
=6/√3+6/1
=2√3+6
donc p(ABC)=4√3+6√2+2√3+6
=6+6√3+6√2
=6(√3+1+√2)