Répondre :
i=5(-3)-3 = [tex] \frac{-15-3}{24-(-12)} = \frac{-18}{36} = \frac{-1}{2} [/tex]
6x4-4(-3)
A=(3.7:0.5-3x0.6)x5=( 0.74-1.8)*[tex] \frac{5}{8} [/tex]= [tex] \frac{5.6*5}{8} = \frac{28}{8} = \frac{7}{2} [/tex]
8
6x4-4(-3)
A=(3.7:0.5-3x0.6)x5=( 0.74-1.8)*[tex] \frac{5}{8} [/tex]= [tex] \frac{5.6*5}{8} = \frac{28}{8} = \frac{7}{2} [/tex]
8
i=(5*(-3)-3) / (6*4-4*(-3))
=(-15-3)/(24+12)
=-18/36
=(18*(-1))/(18*2)
=-1/2
A=(3.7/0.5-3*0.6)*5/8
=(7.4-1.8)*5/8
=5.6*5/8
=3.5
=(-15-3)/(24+12)
=-18/36
=(18*(-1))/(18*2)
=-1/2
A=(3.7/0.5-3*0.6)*5/8
=(7.4-1.8)*5/8
=5.6*5/8
=3.5