Répondre :
Bonsoir
[tex]A=ln(5)\approx1,6\\\\B=-3ln(\dfrac{1}{7})\approx5,8\\\\C=2log(0,8)\approx-0,2[/tex]
[tex]A=ln(5)\approx1,6\\\\B=-3ln(\dfrac{1}{7})\approx5,8\\\\C=2log(0,8)\approx-0,2[/tex]