Répondre :
an(BJS)= tan(32°) = BS/BJ
tan(BIS) = tan(20°) = BS/(BJ+20)
BS = BJ*tan(32°) = tan(20°)*(BJ+20)
on trouve facilement BJ
puis BS
BJ*tan(32°) = tan(20°)*(BJ+20)
BJ*tan(32°) = BJ*tan(20°)+20*tan(20°)
BJ*(tan(32°)-tan(20°)) = 20*tan(20°)
BJ = 20*tan(20°) / (tan(32°)-tan(20°))
BJ 7,2794/0,2609 27,90 m
BS = BJ*tan(32°)
BS 27,90 * 0,62487 17,434 m
Citation :
tan12=20/JS...
JS² = BS² + BJ²
JS 32,90 m
tan(12°) 0,212556561
20/JS 20/32,90 0,6079
tan(12°) 20/JS
tan(BIS) = tan(20°) = BS/(BJ+20)
BS = BJ*tan(32°) = tan(20°)*(BJ+20)
on trouve facilement BJ
puis BS
BJ*tan(32°) = tan(20°)*(BJ+20)
BJ*tan(32°) = BJ*tan(20°)+20*tan(20°)
BJ*(tan(32°)-tan(20°)) = 20*tan(20°)
BJ = 20*tan(20°) / (tan(32°)-tan(20°))
BJ 7,2794/0,2609 27,90 m
BS = BJ*tan(32°)
BS 27,90 * 0,62487 17,434 m
Citation :
tan12=20/JS...
JS² = BS² + BJ²
JS 32,90 m
tan(12°) 0,212556561
20/JS 20/32,90 0,6079
tan(12°) 20/JS