Répondre :
Bonsoir
f o g (x)= (racine(x+2))² - 3racine(x+2)= x+2 - 3racine(x+2) Df: x>-2
g o f (x) = racine (x²-3x+2) = racine ((x-1)(x-2)) Df: x<1 ou x>2
f o g (x)= (racine(x+2))² - 3racine(x+2)= x+2 - 3racine(x+2) Df: x>-2
g o f (x) = racine (x²-3x+2) = racine ((x-1)(x-2)) Df: x<1 ou x>2